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12365555117 is a prime number
BaseRepresentation
bin10111000010000101…
…10110010110101101
31011220202222021200212
423201002312112231
5200311040230432
65403004432205
7615300325046
oct134102662655
934822867625
1012365555117
115276040643
122491248665
131220b05c26
148543b78cd
154c58cd2b2
hex2e10b65ad

12365555117 has 2 divisors, whose sum is σ = 12365555118. Its totient is φ = 12365555116.

The previous prime is 12365555089. The next prime is 12365555123. The reversal of 12365555117 is 71155556321.

12365555117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9389416201 + 2976138916 = 96899^2 + 54554^2 .

It is a cyclic number.

It is not a de Polignac number, because 12365555117 - 214 = 12365538733 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12365555017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6182777558 + 6182777559.

It is an arithmetic number, because the mean of its divisors is an integer number (6182777559).

Almost surely, 212365555117 is an apocalyptic number.

It is an amenable number.

12365555117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12365555117 is an equidigital number, since it uses as much as digits as its factorization.

12365555117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 157500, while the sum is 41.

The spelling of 12365555117 in words is "twelve billion, three hundred sixty-five million, five hundred fifty-five thousand, one hundred seventeen".