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1239155241103 = 13313074826901
BaseRepresentation
bin10010000010000011011…
…010000111000010001111
311101110110212012110010101
4102002003122013002033
5130300242220203403
62345132101151531
7155345264521633
oct22020332070217
94343425173111
101239155241103
1143858291328a
121801a66bb5a7
138cb0c645720
1443d92838dc3
152237745871d
hex1208368708f

1239155241103 has 8 divisors (see below), whose sum is σ = 1377522452096. Its totient is φ = 1106937684000.

The previous prime is 1239155241091. The next prime is 1239155241143. The reversal of 1239155241103 is 3011425519321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1239155241103 - 233 = 1230565306511 is a prime.

It is the 1113174-th Hogben number.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1239155241143) by changing a digit.

It is a nontrivial repunit in base 1113173.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1537413048 + ... + 1537413853.

It is an arithmetic number, because the mean of its divisors is an integer number (172190306512).

Almost surely, 21239155241103 is an apocalyptic number.

1239155241103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1239155241103 is a deficient number, since it is larger than the sum of its proper divisors (138367210993).

1239155241103 is a wasteful number, since it uses less digits than its factorization.

1239155241103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3074826945.

The product of its (nonzero) digits is 32400, while the sum is 37.

The spelling of 1239155241103 in words is "one trillion, two hundred thirty-nine billion, one hundred fifty-five million, two hundred forty-one thousand, one hundred three".

Divisors: 1 13 31 403 3074826901 39972749713 95319633931 1239155241103