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1240112133109 is a prime number
BaseRepresentation
bin10010000010111100011…
…100010111001111110101
311101112221112202121012001
4102002330130113033311
5130304222201224414
62345411042455301
7155411064131353
oct22027434271765
94345845677161
101240112133109
11438a23a73423
12180413064531
138cc3296b505
14440439647d3
15223d1472074
hex120bc7173f5

1240112133109 has 2 divisors, whose sum is σ = 1240112133110. Its totient is φ = 1240112133108.

The previous prime is 1240112133077. The next prime is 1240112133151. The reversal of 1240112133109 is 9013312110421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1235454480100 + 4657653009 = 1111510^2 + 68247^2 .

It is an emirp because it is prime and its reverse (9013312110421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1240112133109 - 25 = 1240112133077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1240112113109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620056066554 + 620056066555.

It is an arithmetic number, because the mean of its divisors is an integer number (620056066555).

Almost surely, 21240112133109 is an apocalyptic number.

It is an amenable number.

1240112133109 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240112133109 is an equidigital number, since it uses as much as digits as its factorization.

1240112133109 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 28.

The spelling of 1240112133109 in words is "one trillion, two hundred forty billion, one hundred twelve million, one hundred thirty-three thousand, one hundred nine".