1240112133151 has 2 divisors, whose sum is σ = 1240112133152. Its totient is φ = 1240112133150.

The previous prime is 1240112133109. The next prime is 1240112133173. The reversal of 1240112133151 is 1513312110421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1240112133151 - 2¹³ = 1240112124959 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1240112131151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620056066575 + 620056066576.

It is an arithmetic number, because the mean of its divisors is an integer number (620056066576).

Almost surely, 2^{1240112133151} is an apocalyptic number.

1240112133151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240112133151 is an equidigital number, since it uses as much as digits as its factorization.

1240112133151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 1240112133151 its reverse (1513312110421), we get a palindrome (2753424243572).

The spelling of 1240112133151 in words is "one trillion, two hundred forty billion, one hundred twelve million, one hundred thirty-three thousand, one hundred fifty-one".