Base | Representation |
---|---|
bin | 10111000110010101… |
… | …10111111111101111 |
3 | 1012000021001220200212 |
4 | 23203022313333233 |
5 | 200344202312143 |
6 | 5410321013035 |
7 | 616212401114 |
oct | 134312677757 |
9 | 35007056625 |
10 | 12401213423 |
11 | 5294186215 |
12 | 24a118417b |
13 | 122830c511 |
14 | 85901a90b |
15 | 4c8ac3918 |
hex | 2e32b7fef |
12401213423 has 2 divisors, whose sum is σ = 12401213424. Its totient is φ = 12401213422.
The previous prime is 12401213411. The next prime is 12401213443. The reversal of 12401213423 is 32431210421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12401213423 - 210 = 12401212399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12401213443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200606711 + 6200606712.
It is an arithmetic number, because the mean of its divisors is an integer number (6200606712).
Almost surely, 212401213423 is an apocalyptic number.
12401213423 is a deficient number, since it is larger than the sum of its proper divisors (1).
12401213423 is an equidigital number, since it uses as much as digits as its factorization.
12401213423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 12401213423 its reverse (32431210421), we get a palindrome (44832423844).
The spelling of 12401213423 in words is "twelve billion, four hundred one million, two hundred thirteen thousand, four hundred twenty-three".
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