1240124332001 has 4 divisors (see below), whose sum is σ = 1240126573104. Its totient is φ = 1240122090900.

The previous prime is 1240124331997. The next prime is 1240124332019. The reversal of 1240124332001 is 1002334210421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1240124332001 - 2² = 1240124331997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1240124332021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 373466 + ... + 1618556.

It is an arithmetic number, because the mean of its divisors is an integer number (310031643276).

Almost surely, 2^{1240124332001} is an apocalyptic number.

It is an amenable number.

1240124332001 is a deficient number, since it is larger than the sum of its proper divisors (2241103).

1240124332001 is an equidigital number, since it uses as much as digits as its factorization.

1240124332001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2241102.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1240124332001 its reverse (1002334210421), we get a palindrome (2242458542422).

The spelling of 1240124332001 in words is "one trillion, two hundred forty billion, one hundred twenty-four million, three hundred thirty-two thousand, one".