1240124332019 has 2 divisors, whose sum is σ = 1240124332020. Its totient is φ = 1240124332018.

The previous prime is 1240124331997. The next prime is 1240124332021. The reversal of 1240124332019 is 9102334210421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1240124332019 - 2⁸ = 1240124331763 is a prime.

It is a super-2 number, since 2×1240124332019² (a number of 25 digits) contains 22 as substring.

Together with 1240124332021, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1240124332039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620062166009 + 620062166010.

It is an arithmetic number, because the mean of its divisors is an integer number (620062166010).

Almost surely, 2^{1240124332019} is an apocalyptic number.

1240124332019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240124332019 is an equidigital number, since it uses as much as digits as its factorization.

1240124332019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 32.

The spelling of 1240124332019 in words is "one trillion, two hundred forty billion, one hundred twenty-four million, three hundred thirty-two thousand, nineteen".