Base | Representation |
---|---|
bin | 111001101111111000… |
… | …1010110010111100101 |
3 | 102212002200222102011121 |
4 | 1303133301112113211 |
5 | 4012434403341013 |
6 | 132545420133541 |
7 | 11650110666334 |
oct | 1633761262745 |
9 | 385080872147 |
10 | 124013340133 |
11 | 4865932aa51 |
12 | 2004b9972b1 |
13 | b9047c9a47 |
14 | 600636dd1b |
15 | 335c4b358d |
hex | 1cdfc565e5 |
124013340133 has 16 divisors (see below), whose sum is σ = 128329883136. Its totient is φ = 119759391360.
The previous prime is 124013340089. The next prime is 124013340149. The reversal of 124013340133 is 331043310421.
It is a cyclic number.
It is not a de Polignac number, because 124013340133 - 29 = 124013339621 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 124013340098 and 124013340107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (124013340163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11679735 + ... + 11690347.
It is an arithmetic number, because the mean of its divisors is an integer number (8020617696).
Almost surely, 2124013340133 is an apocalyptic number.
It is an amenable number.
124013340133 is a deficient number, since it is larger than the sum of its proper divisors (4316543003).
124013340133 is a wasteful number, since it uses less digits than its factorization.
124013340133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13524.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 124013340133 its reverse (331043310421), we get a palindrome (455056650554).
The spelling of 124013340133 in words is "one hundred twenty-four billion, thirteen million, three hundred forty thousand, one hundred thirty-three".
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