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12401340000000 = 28357729527
BaseRepresentation
bin1011010001110110100101…
…1101110010011100000000
31121220120000201002112012220
42310131221131302130000
53111140421020000000
642213032535051040
72416652523512040
oct264355135623400
947816021075186
1012401340000000
113a51419145016
121483567810a80
136bc59782c723
1430c329b15720
151678c22ab1a0
hexb4769772700

12401340000000 has 576 divisors, whose sum is σ = 47152404289536. Its totient is φ = 2834496000000.

The previous prime is 12401339999981. The next prime is 12401340000011. The reversal of 12401340000000 is 4310421.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 419985237 + ... + 420014763.

Almost surely, 212401340000000 is an apocalyptic number.

12401340000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12401340000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (23576202144768).

12401340000000 is an abundant number, since it is smaller than the sum of its proper divisors (34751064289536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12401340000000 is an frugal number, since it uses more digits than its factorization.

12401340000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29588 (or 29544 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 12401340000000 its reverse (4310421), we get a palindrome (12401344310421).

The spelling of 12401340000000 in words is "twelve trillion, four hundred one billion, three hundred forty million", and thus it is an aban number.