124014113 has 4 divisors (see below), whose sum is σ = 125407620. Its totient is φ = 122620608.

The previous prime is 124014109. The next prime is 124014157. The reversal of 124014113 is 311410421.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311410421 = 7 ⋅44487203.

It can be written as a sum of positive squares in 2 ways, for example, as 59243809 + 64770304 = 7697^2 + 8048^2 .

It is a cyclic number.

It is not a de Polignac number, because 124014113 - 2² = 124014109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 124014091 and 124014100.

It is not an unprimeable number, because it can be changed into a prime (124010113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 696620 + ... + 696797.

It is an arithmetic number, because the mean of its divisors is an integer number (31351905).

Almost surely, 2^124014113 is an apocalyptic number.

It is an amenable number.

124014113 is a deficient number, since it is larger than the sum of its proper divisors (1393507).

124014113 is an equidigital number, since it uses as much as digits as its factorization.

124014113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1393506.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 124014113 is about 11136.1624000371. The cubic root of 124014113 is about 498.6820128725.

Adding to 124014113 its reverse (311410421), we get a palindrome (435424534).

The spelling of 124014113 in words is "one hundred twenty-four million, fourteen thousand, one hundred thirteen".