Base | Representation |
---|---|
bin | 10111000110010111… |
… | …01101000111011011 |
3 | 1012000021110222011101 |
4 | 23203023231013123 |
5 | 200344231243003 |
6 | 5410325412231 |
7 | 616214265343 |
oct | 134313550733 |
9 | 35007428141 |
10 | 12401431003 |
11 | 5294314735 |
12 | 24a126a077 |
13 | 1228387570 |
14 | 859075d23 |
15 | 4c8b1811d |
hex | 2e32ed1db |
12401431003 has 4 divisors (see below), whose sum is σ = 13355387248. Its totient is φ = 11447474760.
The previous prime is 12401430971. The next prime is 12401431033. The reversal of 12401431003 is 30013410421.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30013410421 = 4967 ⋅6042563.
It is a cyclic number.
It is not a de Polignac number, because 12401431003 - 25 = 12401430971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12401431033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 476978103 + ... + 476978128.
It is an arithmetic number, because the mean of its divisors is an integer number (3338846812).
Almost surely, 212401431003 is an apocalyptic number.
12401431003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12401431003 is a deficient number, since it is larger than the sum of its proper divisors (953956245).
12401431003 is an equidigital number, since it uses as much as digits as its factorization.
12401431003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 953956244.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 12401431003 its reverse (30013410421), we get a palindrome (42414841424).
The spelling of 12401431003 in words is "twelve billion, four hundred one million, four hundred thirty-one thousand, three".
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