Base | Representation |
---|---|
bin | 10010000010111110110… |
… | …101111110100011010111 |
3 | 11101120001100112110220110 |
4 | 102002332311332203113 |
5 | 130304313003332020 |
6 | 2345415041534103 |
7 | 155412063326643 |
oct | 22027665764327 |
9 | 4346040473813 |
10 | 1240152402135 |
11 | 438a44778109 |
12 | 180424644333 |
13 | 8cc3b0ca63a |
14 | 44049047c23 |
15 | 223d4c788e0 |
hex | 120bed7e8d7 |
1240152402135 has 16 divisors (see below), whose sum is σ = 1995713465184. Its totient is φ = 657591407232.
The previous prime is 1240152402133. The next prime is 1240152402163. The reversal of 1240152402135 is 5312042510421.
It is not a de Polignac number, because 1240152402135 - 21 = 1240152402133 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1240152402133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 238947772 + ... + 238952961.
It is an arithmetic number, because the mean of its divisors is an integer number (124732091574).
Almost surely, 21240152402135 is an apocalyptic number.
1240152402135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1240152402135 is a deficient number, since it is larger than the sum of its proper divisors (755561063049).
1240152402135 is a wasteful number, since it uses less digits than its factorization.
1240152402135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 477900914.
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 1240152402135 its reverse (5312042510421), we get a palindrome (6552194912556).
The spelling of 1240152402135 in words is "one trillion, two hundred forty billion, one hundred fifty-two million, four hundred two thousand, one hundred thirty-five".
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