12401530335 has 12 divisors (see below), whose sum is σ = 21495985992. Its totient is φ = 6614149488.

The previous prime is 12401530327. The next prime is 12401530343. The reversal of 12401530335 is 53303510421.

12401530335 is a `hidden beast` number, since 124 + 0 + 1 + 530 + 3 + 3 + 5 = 666.

It is an interprime number because it is at equal distance from previous prime (12401530327) and next prime (12401530343).

It is not a de Polignac number, because 12401530335 - 2³ = 12401530327 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12401530299 and 12401530308.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 137794737 + ... + 137794826.

It is an arithmetic number, because the mean of its divisors is an integer number (1791332166).

Almost surely, 2^12401530335 is an apocalyptic number.

12401530335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12401530335 is a deficient number, since it is larger than the sum of its proper divisors (9094455657).

12401530335 is a wasteful number, since it uses less digits than its factorization.

12401530335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 275589574 (or 275589571 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 27.

The spelling of 12401530335 in words is "twelve billion, four hundred one million, five hundred thirty thousand, three hundred thirty-five".