Base | Representation |
---|---|
bin | 1110110010001… |
… | …11000101001001 |
3 | 22122101000201122 |
4 | 13121013011021 |
5 | 223222214423 |
6 | 20150125025 |
7 | 3034115264 |
oct | 731070511 |
9 | 278330648 |
10 | 124023113 |
11 | 6400a445 |
12 | 35650775 |
13 | 1c905176 |
14 | 12685cdb |
15 | ad4c8c8 |
hex | 7647149 |
124023113 has 2 divisors, whose sum is σ = 124023114. Its totient is φ = 124023112.
The previous prime is 124023103. The next prime is 124023209. The reversal of 124023113 is 311320421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 120736144 + 3286969 = 10988^2 + 1813^2 .
It is a cyclic number.
It is not a de Polignac number, because 124023113 - 26 = 124023049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 124023091 and 124023100.
It is not a weakly prime, because it can be changed into another prime (124023103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62011556 + 62011557.
It is an arithmetic number, because the mean of its divisors is an integer number (62011557).
Almost surely, 2124023113 is an apocalyptic number.
It is an amenable number.
124023113 is a deficient number, since it is larger than the sum of its proper divisors (1).
124023113 is an equidigital number, since it uses as much as digits as its factorization.
124023113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 124023113 is about 11136.5664816406. The cubic root of 124023113 is about 498.6940760951.
Adding to 124023113 its reverse (311320421), we get a palindrome (435343534).
The spelling of 124023113 in words is "one hundred twenty-four million, twenty-three thousand, one hundred thirteen".
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