Base | Representation |
---|---|
bin | 11100001100111001101111… |
… | …111001110100001100000111 |
3 | 121021011100010100212022022202 |
4 | 130030321233321310030013 |
5 | 112224114404402011324 |
6 | 1115443253224145115 |
7 | 35061004113212516 |
oct | 3414715771641407 |
9 | 537140110768282 |
10 | 124031943000839 |
11 | 3657a719355125 |
12 | 11ab227a90819b |
13 | 5429214cc8723 |
14 | 228b26c8b667d |
15 | e5154eadd8ae |
hex | 70ce6fe74307 |
124031943000839 has 2 divisors, whose sum is σ = 124031943000840. Its totient is φ = 124031943000838.
The previous prime is 124031943000829. The next prime is 124031943000907. The reversal of 124031943000839 is 938000349130421.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-124031943000839 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 124031943000793 and 124031943000802.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124031943000829) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62015971500419 + 62015971500420.
It is an arithmetic number, because the mean of its divisors is an integer number (62015971500420).
Almost surely, 2124031943000839 is an apocalyptic number.
124031943000839 is a deficient number, since it is larger than the sum of its proper divisors (1).
124031943000839 is an equidigital number, since it uses as much as digits as its factorization.
124031943000839 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 47.
The spelling of 124031943000839 in words is "one hundred twenty-four trillion, thirty-one billion, nine hundred forty-three million, eight hundred thirty-nine", and thus it is an aban number.
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