12404013 has 4 divisors (see below), whose sum is σ = 16538688. Its totient is φ = 8269340.

The previous prime is 12404011. The next prime is 12404023. The reversal of 12404013 is 31040421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12404013 - 2¹ = 12404011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12403983 and 12404001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12404011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2067333 + ... + 2067338.

It is an arithmetic number, because the mean of its divisors is an integer number (4134672).

Almost surely, 2^12404013 is an apocalyptic number.

It is an amenable number.

12404013 is a deficient number, since it is larger than the sum of its proper divisors (4134675).

12404013 is an equidigital number, since it uses as much as digits as its factorization.

12404013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4134674.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 12404013 is about 3521.9331339479. The cubic root of 12404013 is about 231.4838717000.

Adding to 12404013 its reverse (31040421), we get a palindrome (43444434).

It can be divided in two parts, 1240 and 4013, that added together give a triangular number (5253 = T₁₀₂).

The spelling of 12404013 in words is "twelve million, four hundred four thousand, thirteen".