12404013102023 has 2 divisors, whose sum is σ = 12404013102024. Its totient is φ = 12404013102022.

The previous prime is 12404013101983. The next prime is 12404013102029. The reversal of 12404013102023 is 32020131040421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12404013102023 - 2³⁶ = 12335293625287 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12404013102023.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12404013102029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6202006551011 + 6202006551012.

It is an arithmetic number, because the mean of its divisors is an integer number (6202006551012).

Almost surely, 2^{12404013102023} is an apocalyptic number.

12404013102023 is a deficient number, since it is larger than the sum of its proper divisors (1).

12404013102023 is an equidigital number, since it uses as much as digits as its factorization.

12404013102023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12404013102023 its reverse (32020131040421), we get a palindrome (44424144142444).

The spelling of 12404013102023 in words is "twelve trillion, four hundred four billion, thirteen million, one hundred two thousand, twenty-three".