Base | Representation |
---|---|
bin | 1011010010000000100011… |
… | …0010110111110001100110 |
3 | 1121220210221000000021212021 |
4 | 2310200020302313301212 |
5 | 3111211404323313410 |
6 | 42214154105013354 |
7 | 2420106002515606 |
oct | 264401062676146 |
9 | 47823830007767 |
10 | 12404013104230 |
11 | 3a52570030870 |
12 | 1483b92a8425a |
13 | 6bc90258a0c7 |
14 | 30c500b46c06 |
15 | 1679cbccbeda |
hex | b4808cb7c66 |
12404013104230 has 32 divisors (see below), whose sum is σ = 24363997309440. Its totient is φ = 4509249085920.
The previous prime is 12404013104213. The next prime is 12404013104293. The reversal of 12404013104230 is 3240131040421.
It is a junction number, because it is equal to n+sod(n) for n = 12404013104195 and 12404013104204.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15881070 + ... + 16643809.
It is an arithmetic number, because the mean of its divisors is an integer number (761374915920).
Almost surely, 212404013104230 is an apocalyptic number.
12404013104230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12404013104230 is a deficient number, since it is larger than the sum of its proper divisors (11959984205210).
12404013104230 is a wasteful number, since it uses less digits than its factorization.
12404013104230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32528364.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12404013104230 its reverse (3240131040421), we get a palindrome (15644144144651).
The spelling of 12404013104230 in words is "twelve trillion, four hundred four billion, thirteen million, one hundred four thousand, two hundred thirty".
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