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124043433121 is a prime number
BaseRepresentation
bin111001110000110010…
…0001001010010100001
3102212011210121021222201
41303201210021102201
54013020104324441
6132552413133201
711650624533106
oct1634144112241
9385153537881
10124043433121
1148674314293
1220059a8a201
13b90ab0514a
14600a364aad
15335ee59c31
hex1ce19094a1

124043433121 has 2 divisors, whose sum is σ = 124043433122. Its totient is φ = 124043433120.

The previous prime is 124043433119. The next prime is 124043433167. The reversal of 124043433121 is 121334340421.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124030752400 + 12680721 = 352180^2 + 3561^2 .

It is a cyclic number.

It is not a de Polignac number, because 124043433121 - 21 = 124043433119 is a prime.

Together with 124043433119, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 124043433121.

It is not a weakly prime, because it can be changed into another prime (124043433721) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62021716560 + 62021716561.

It is an arithmetic number, because the mean of its divisors is an integer number (62021716561).

Almost surely, 2124043433121 is an apocalyptic number.

It is an amenable number.

124043433121 is a deficient number, since it is larger than the sum of its proper divisors (1).

124043433121 is an equidigital number, since it uses as much as digits as its factorization.

124043433121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 124043433121 its reverse (121334340421), we get a palindrome (245377773542).

The spelling of 124043433121 in words is "one hundred twenty-four billion, forty-three million, four hundred thirty-three thousand, one hundred twenty-one".