Base | Representation |
---|---|
bin | 11100001101000110001110… |
… | …101011000100100101111100 |
3 | 121021012121201022110021112121 |
4 | 130031012032223010211330 |
5 | 112224324331044201302 |
6 | 1115453351105012324 |
7 | 35061660160021252 |
oct | 3415061653044574 |
9 | 537177638407477 |
10 | 124045344131452 |
11 | 365853759a7987 |
12 | 11ab499a9240a4 |
13 | 542a56c516503 |
14 | 228bb8061c5d2 |
15 | e51a86378e37 |
hex | 70d18eac497c |
124045344131452 has 12 divisors (see below), whose sum is σ = 228504581294920. Its totient is φ = 58758320904336.
The previous prime is 124045344131413. The next prime is 124045344131479. The reversal of 124045344131452 is 254131443540421.
It is a junction number, because it is equal to n+sod(n) for n = 124045344131399 and 124045344131408.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 816087790263 + ... + 816087790414.
Almost surely, 2124045344131452 is an apocalyptic number.
It is an amenable number.
124045344131452 is a deficient number, since it is larger than the sum of its proper divisors (104459237163468).
124045344131452 is a wasteful number, since it uses less digits than its factorization.
124045344131452 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1632175580700 (or 1632175580698 counting only the distinct ones).
The product of its (nonzero) digits is 921600, while the sum is 43.
Adding to 124045344131452 its reverse (254131443540421), we get a palindrome (378176787671873).
The spelling of 124045344131452 in words is "one hundred twenty-four trillion, forty-five billion, three hundred forty-four million, one hundred thirty-one thousand, four hundred fifty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •