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124055413121909 is a prime number
BaseRepresentation
bin11100001101001111100110…
…110101001110001101110101
3121021020120201001000222210002
4130031033212311032031311
5112230010441224400114
61115502134154241045
735062464533023463
oct3415174665161565
9537216631028702
10124055413121909
11365896726534a5
1211ab692aa26185
13542b4b55aab29
14228c4579bd833
15e51e753137de
hex70d3e6d4e375

124055413121909 has 2 divisors, whose sum is σ = 124055413121910. Its totient is φ = 124055413121908.

The previous prime is 124055413121881. The next prime is 124055413121911. The reversal of 124055413121909 is 909121314550421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122950175124100 + 1105237997809 = 11088290^2 + 1051303^2 .

It is a cyclic number.

It is not a de Polignac number, because 124055413121909 - 216 = 124055413056373 is a prime.

Together with 124055413121911, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124055413129909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62027706560954 + 62027706560955.

It is an arithmetic number, because the mean of its divisors is an integer number (62027706560955).

Almost surely, 2124055413121909 is an apocalyptic number.

It is an amenable number.

124055413121909 is a deficient number, since it is larger than the sum of its proper divisors (1).

124055413121909 is an equidigital number, since it uses as much as digits as its factorization.

124055413121909 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 388800, while the sum is 47.

The spelling of 124055413121909 in words is "one hundred twenty-four trillion, fifty-five billion, four hundred thirteen million, one hundred twenty-one thousand, nine hundred nine".