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12405544000327 is a prime number
BaseRepresentation
bin1011010010000110010000…
…0010110001101101000111
31121220221212200122212111201
42310201210002301231013
53111223023231002302
642215010033243331
72420161642103542
oct264414402615507
947827780585451
1012405544000327
113a531861a3755
12148433b703547
136bcab77a919a
1430c6081ad859
15167a6b3cac87
hexb48640b1b47

12405544000327 has 2 divisors, whose sum is σ = 12405544000328. Its totient is φ = 12405544000326.

The previous prime is 12405544000321. The next prime is 12405544000517. The reversal of 12405544000327 is 72300044550421.

It is a weak prime.

It is an emirp because it is prime and its reverse (72300044550421) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12405544000327 is a prime.

It is a super-2 number, since 2×124055440003272 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12405544000321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6202772000163 + 6202772000164.

It is an arithmetic number, because the mean of its divisors is an integer number (6202772000164).

Almost surely, 212405544000327 is an apocalyptic number.

12405544000327 is a deficient number, since it is larger than the sum of its proper divisors (1).

12405544000327 is an equidigital number, since it uses as much as digits as its factorization.

12405544000327 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 134400, while the sum is 37.

Adding to 12405544000327 its reverse (72300044550421), we get a palindrome (84705588550748).

The spelling of 12405544000327 in words is "twelve trillion, four hundred five billion, five hundred forty-four million, three hundred twenty-seven", and thus it is an aban number.