Base | Representation |
---|---|
bin | 1011010010000110010000… |
… | …0010110001110000000101 |
3 | 1121220221212200122212202202 |
4 | 2310201210002301300011 |
5 | 3111223023231004032 |
6 | 42215010033244245 |
7 | 2420161642104233 |
oct | 264414402616005 |
9 | 47827780585682 |
10 | 12405544000517 |
11 | 3a531861a3908 |
12 | 148433b703685 |
13 | 6bcab77a92b5 |
14 | 30c6081ad953 |
15 | 167a6b3cad62 |
hex | b48640b1c05 |
12405544000517 has 2 divisors, whose sum is σ = 12405544000518. Its totient is φ = 12405544000516.
The previous prime is 12405544000327. The next prime is 12405544000621. The reversal of 12405544000517 is 71500044550421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8892884624836 + 3512659375681 = 2982094^2 + 1874209^2 .
It is a cyclic number.
It is not a de Polignac number, because 12405544000517 - 220 = 12405542951941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12405544900517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6202772000258 + 6202772000259.
It is an arithmetic number, because the mean of its divisors is an integer number (6202772000259).
Almost surely, 212405544000517 is an apocalyptic number.
It is an amenable number.
12405544000517 is a deficient number, since it is larger than the sum of its proper divisors (1).
12405544000517 is an equidigital number, since it uses as much as digits as its factorization.
12405544000517 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112000, while the sum is 38.
Adding to 12405544000517 its reverse (71500044550421), we get a palindrome (83905588550938).
The spelling of 12405544000517 in words is "twelve trillion, four hundred five billion, five hundred forty-four million, five hundred seventeen", and thus it is an aban number.
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