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12410404133 is a prime number
BaseRepresentation
bin10111000111011011…
…11011110100100101
31012000220100211222112
423203231323310211
5200404030413013
65411250010405
7616353460151
oct134355736445
935026324875
1012410404133
115299393346
1224a4276a05
13122a1a98ca
1485a330061
154c97dbba8
hex2e3b7bd25

12410404133 has 2 divisors, whose sum is σ = 12410404134. Its totient is φ = 12410404132.

The previous prime is 12410404129. The next prime is 12410404163. The reversal of 12410404133 is 33140401421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12170061124 + 240343009 = 110318^2 + 15503^2 .

It is a cyclic number.

It is not a de Polignac number, because 12410404133 - 22 = 12410404129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12410404099 and 12410404108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12410404163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6205202066 + 6205202067.

It is an arithmetic number, because the mean of its divisors is an integer number (6205202067).

Almost surely, 212410404133 is an apocalyptic number.

It is an amenable number.

12410404133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12410404133 is an equidigital number, since it uses as much as digits as its factorization.

12410404133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12410404133 its reverse (33140401421), we get a palindrome (45550805554).

The spelling of 12410404133 in words is "twelve billion, four hundred ten million, four hundred four thousand, one hundred thirty-three".