124113433438 has 8 divisors (see below), whose sum is σ = 186196003632. Its totient is φ = 62048098896.

The previous prime is 124113433429. The next prime is 124113433439. The reversal of 124113433438 is 834334311421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 124113433397 and 124113433406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (124113433439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4290895 + ... + 4319722.

It is an arithmetic number, because the mean of its divisors is an integer number (23274500454).

Almost surely, 2^124113433438 is an apocalyptic number.

124113433438 is a deficient number, since it is larger than the sum of its proper divisors (62082570194).

124113433438 is an equidigital number, since it uses as much as digits as its factorization.

124113433438 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8617826.

The product of its digits is 82944, while the sum is 37.

Adding to 124113433438 its reverse (834334311421), we get a palindrome (958447744859).

The spelling of 124113433438 in words is "one hundred twenty-four billion, one hundred thirteen million, four hundred thirty-three thousand, four hundred thirty-eight".