1241243313431 has 4 divisors (see below), whose sum is σ = 1354083614664. Its totient is φ = 1128403012200.

The previous prime is 1241243313421. The next prime is 1241243313461. The reversal of 1241243313431 is 1343133421421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1241243313431 is a prime.

It is a super-2 number, since 2×1241243313431² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1241243313421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56420150600 + ... + 56420150621.

It is an arithmetic number, because the mean of its divisors is an integer number (338520903666).

Almost surely, 2^{1241243313431} is an apocalyptic number.

1241243313431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1241243313431 is a deficient number, since it is larger than the sum of its proper divisors (112840301233).

1241243313431 is a wasteful number, since it uses less digits than its factorization.

1241243313431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 112840301232.

The product of its digits is 20736, while the sum is 32.

Adding to 1241243313431 its reverse (1343133421421), we get a palindrome (2584376734852).

The spelling of 1241243313431 in words is "one trillion, two hundred forty-one billion, two hundred forty-three million, three hundred thirteen thousand, four hundred thirty-one".