Base | Representation |
---|---|
bin | 100100111111100… |
… | …1110100011001001 |
3 | 10012111202011011112 |
4 | 1021333032203021 |
5 | 10020233431213 |
6 | 323101340105 |
7 | 42521654525 |
oct | 11177164311 |
9 | 3174664145 |
10 | 1241311433 |
11 | 58776271a |
12 | 2a7867635 |
13 | 16a229c0b |
14 | bac04d85 |
15 | 73e9aea8 |
hex | 49fce8c9 |
1241311433 has 2 divisors, whose sum is σ = 1241311434. Its totient is φ = 1241311432.
The previous prime is 1241311417. The next prime is 1241311459. The reversal of 1241311433 is 3341131421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1063542544 + 177768889 = 32612^2 + 13333^2 .
It is a cyclic number.
It is not a de Polignac number, because 1241311433 - 24 = 1241311417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1241311399 and 1241311408.
It is not a weakly prime, because it can be changed into another prime (1241311133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620655716 + 620655717.
It is an arithmetic number, because the mean of its divisors is an integer number (620655717).
Almost surely, 21241311433 is an apocalyptic number.
It is an amenable number.
1241311433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1241311433 is an equidigital number, since it uses as much as digits as its factorization.
1241311433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 864, while the sum is 23.
The square root of 1241311433 is about 35232.2498997722. The cubic root of 1241311433 is about 1074.7156797751.
Adding to 1241311433 its reverse (3341131421), we get a palindrome (4582442854).
The spelling of 1241311433 in words is "one billion, two hundred forty-one million, three hundred eleven thousand, four hundred thirty-three".
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