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124132122131 is a prime number
BaseRepresentation
bin111001110011011011…
…0011101111000010011
3102212101222111011102212
41303212312131320103
54013210310402011
6133005302102335
711653052425463
oct1634666357023
9385358434385
10124132122131
114870a38a696
122008371a9ab
13b9232b8454
14601804dba3
153367b2808b
hex1ce6d9de13

124132122131 has 2 divisors, whose sum is σ = 124132122132. Its totient is φ = 124132122130.

The previous prime is 124132122097. The next prime is 124132122133. The reversal of 124132122131 is 131221231421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 124132122131 - 26 = 124132122067 is a prime.

It is a super-2 number, since 2×1241321221312 (a number of 23 digits) contains 22 as substring.

Together with 124132122133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 124132122097 and 124132122106.

It is not a weakly prime, because it can be changed into another prime (124132122133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62066061065 + 62066061066.

It is an arithmetic number, because the mean of its divisors is an integer number (62066061066).

Almost surely, 2124132122131 is an apocalyptic number.

124132122131 is a deficient number, since it is larger than the sum of its proper divisors (1).

124132122131 is an equidigital number, since it uses as much as digits as its factorization.

124132122131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 576, while the sum is 23.

Adding to 124132122131 its reverse (131221231421), we get a palindrome (255353353552).

The spelling of 124132122131 in words is "one hundred twenty-four billion, one hundred thirty-two million, one hundred twenty-two thousand, one hundred thirty-one".