12413233231457 has 2 divisors, whose sum is σ = 12413233231458. Its totient is φ = 12413233231456.

The previous prime is 12413233231417. The next prime is 12413233231459. The reversal of 12413233231457 is 75413233231421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11767582412881 + 645650818576 = 3430391^2 + 803524^2 .

It is an emirp because it is prime and its reverse (75413233231421) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12413233231457 is a prime.

Together with 12413233231459, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12413233231459) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6206616615728 + 6206616615729.

It is an arithmetic number, because the mean of its divisors is an integer number (6206616615729).

Almost surely, 2^{12413233231457} is an apocalyptic number.

It is an amenable number.

12413233231457 is a deficient number, since it is larger than the sum of its proper divisors (1).

12413233231457 is an equidigital number, since it uses as much as digits as its factorization.

12413233231457 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 362880, while the sum is 41.

Adding to 12413233231457 its reverse (75413233231421), we get a palindrome (87826466462878).

The spelling of 12413233231457 in words is "twelve trillion, four hundred thirteen billion, two hundred thirty-three million, two hundred thirty-one thousand, four hundred fifty-seven".