Base | Representation |
---|---|
bin | 111001110011101100… |
… | …1111100001100100111 |
3 | 102212102121222121120102 |
4 | 1303213121330030213 |
5 | 4013220200440401 |
6 | 133010233254315 |
7 | 11653224446063 |
oct | 1634731741447 |
9 | 385377877512 |
10 | 124141421351 |
11 | 487146612a2 |
12 | 2008686439b |
13 | b9251c304c |
14 | 6019390aa3 |
15 | 336886356b |
hex | 1ce767c327 |
124141421351 has 2 divisors, whose sum is σ = 124141421352. Its totient is φ = 124141421350.
The previous prime is 124141421311. The next prime is 124141421353. The reversal of 124141421351 is 153124141421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 124141421351 - 210 = 124141420327 is a prime.
It is a super-2 number, since 2×1241414213512 (a number of 23 digits) contains 22 as substring.
Together with 124141421353, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124141421353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62070710675 + 62070710676.
It is an arithmetic number, because the mean of its divisors is an integer number (62070710676).
Almost surely, 2124141421351 is an apocalyptic number.
124141421351 is a deficient number, since it is larger than the sum of its proper divisors (1).
124141421351 is an equidigital number, since it uses as much as digits as its factorization.
124141421351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3840, while the sum is 29.
Adding to 124141421351 its reverse (153124141421), we get a palindrome (277265562772).
The spelling of 124141421351 in words is "one hundred twenty-four billion, one hundred forty-one million, four hundred twenty-one thousand, three hundred fifty-one".
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