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124141421351 is a prime number
BaseRepresentation
bin111001110011101100…
…1111100001100100111
3102212102121222121120102
41303213121330030213
54013220200440401
6133010233254315
711653224446063
oct1634731741447
9385377877512
10124141421351
11487146612a2
122008686439b
13b9251c304c
146019390aa3
15336886356b
hex1ce767c327

124141421351 has 2 divisors, whose sum is σ = 124141421352. Its totient is φ = 124141421350.

The previous prime is 124141421311. The next prime is 124141421353. The reversal of 124141421351 is 153124141421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 124141421351 - 210 = 124141420327 is a prime.

It is a super-2 number, since 2×1241414213512 (a number of 23 digits) contains 22 as substring.

Together with 124141421353, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (124141421353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62070710675 + 62070710676.

It is an arithmetic number, because the mean of its divisors is an integer number (62070710676).

Almost surely, 2124141421351 is an apocalyptic number.

124141421351 is a deficient number, since it is larger than the sum of its proper divisors (1).

124141421351 is an equidigital number, since it uses as much as digits as its factorization.

124141421351 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3840, while the sum is 29.

Adding to 124141421351 its reverse (153124141421), we get a palindrome (277265562772).

The spelling of 124141421351 in words is "one hundred twenty-four billion, one hundred forty-one million, four hundred twenty-one thousand, three hundred fifty-one".