Base | Representation |
---|---|
bin | 10010000100001010110… |
… | …110001001000000111111 |
3 | 11101200100012212211201212 |
4 | 102010022312021000333 |
5 | 130314420420412112 |
6 | 2350145351555035 |
7 | 155455505520344 |
oct | 22041266110077 |
9 | 4350305784655 |
10 | 1241427513407 |
11 | 439539516084 |
12 | 18071b68ba7b |
13 | 900b232cc53 |
14 | 4412a52a7cb |
15 | 2245bb9e522 |
hex | 1210ad8903f |
1241427513407 has 4 divisors (see below), whose sum is σ = 1246755528720. Its totient is φ = 1236099498096.
The previous prime is 1241427513397. The next prime is 1241427513421. The reversal of 1241427513407 is 7043157241421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1241427513407 - 224 = 1241410736191 is a prime.
It is a super-2 number, since 2×12414275134072 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1241427513607) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2664007307 + ... + 2664007772.
It is an arithmetic number, because the mean of its divisors is an integer number (311688882180).
Almost surely, 21241427513407 is an apocalyptic number.
1241427513407 is a deficient number, since it is larger than the sum of its proper divisors (5328015313).
1241427513407 is an equidigital number, since it uses as much as digits as its factorization.
1241427513407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5328015312.
The product of its (nonzero) digits is 188160, while the sum is 41.
The spelling of 1241427513407 in words is "one trillion, two hundred forty-one billion, four hundred twenty-seven million, five hundred thirteen thousand, four hundred seven".
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