Base | Representation |
---|---|
bin | 10010000100110011000… |
… | …111011001010010010111 |
3 | 11101202002022011110210202 |
4 | 102010303013121102113 |
5 | 130322311400001033 |
6 | 2350340404411115 |
7 | 155511321235016 |
oct | 22046307312227 |
9 | 4352068143722 |
10 | 1242103125143 |
11 | 439855918191 |
12 | 1808899a6a9b |
13 | 9018c2b06ca |
14 | 44192156a7d |
15 | 2249b1558e8 |
hex | 121331d9497 |
1242103125143 has 2 divisors, whose sum is σ = 1242103125144. Its totient is φ = 1242103125142.
The previous prime is 1242103125083. The next prime is 1242103125217. The reversal of 1242103125143 is 3415213012421.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1242103125143 - 26 = 1242103125079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1242103185143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621051562571 + 621051562572.
It is an arithmetic number, because the mean of its divisors is an integer number (621051562572).
Almost surely, 21242103125143 is an apocalyptic number.
1242103125143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1242103125143 is an equidigital number, since it uses as much as digits as its factorization.
1242103125143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 1242103125143 its reverse (3415213012421), we get a palindrome (4657316137564).
The spelling of 1242103125143 in words is "one trillion, two hundred forty-two billion, one hundred three million, one hundred twenty-five thousand, one hundred forty-three".
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