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12421254023653 is a prime number
BaseRepresentation
bin1011010011000000110001…
…1011110000100111100101
31121222110102112211202002111
42310300030123300213211
53112002212012224103
642230124553441021
72421256153102036
oct264601433604745
947873375752074
1012421254023653
113a59908090802
1214873a4a10171
136c141c463987
1430d29881aa8d
1516818a6e286d
hexb4c0c6f09e5

12421254023653 has 2 divisors, whose sum is σ = 12421254023654. Its totient is φ = 12421254023652.

The previous prime is 12421254023621. The next prime is 12421254023693. The reversal of 12421254023653 is 35632045212421.

It is an a-pointer prime, because the next prime (12421254023693) can be obtained adding 12421254023653 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9008744122849 + 3412509900804 = 3001457^2 + 1847298^2 .

It is a cyclic number.

It is not a de Polignac number, because 12421254023653 - 25 = 12421254023621 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12421254023693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6210627011826 + 6210627011827.

It is an arithmetic number, because the mean of its divisors is an integer number (6210627011827).

Almost surely, 212421254023653 is an apocalyptic number.

It is an amenable number.

12421254023653 is a deficient number, since it is larger than the sum of its proper divisors (1).

12421254023653 is an equidigital number, since it uses as much as digits as its factorization.

12421254023653 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 345600, while the sum is 40.

The spelling of 12421254023653 in words is "twelve trillion, four hundred twenty-one billion, two hundred fifty-four million, twenty-three thousand, six hundred fifty-three".