12421254024541 has 2 divisors, whose sum is σ = 12421254024542. Its totient is φ = 12421254024540.

The previous prime is 12421254024533. The next prime is 12421254024559. The reversal of 12421254024541 is 14542045212421.

It is a happy number.

12421254024541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11388701331225 + 1032552693316 = 3374715^2 + 1016146^2 .

It is a cyclic number.

It is not a de Polignac number, because 12421254024541 - 2³ = 12421254024533 is a prime.

It is a super-3 number, since 3×12421254024541³ (a number of 40 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12421254024541.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12421254024241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6210627012270 + 6210627012271.

It is an arithmetic number, because the mean of its divisors is an integer number (6210627012271).

Almost surely, 2^{12421254024541} is an apocalyptic number.

It is an amenable number.

12421254024541 is a deficient number, since it is larger than the sum of its proper divisors (1).

12421254024541 is an equidigital number, since it uses as much as digits as its factorization.

12421254024541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 102400, while the sum is 37.

Adding to 12421254024541 its reverse (14542045212421), we get a palindrome (26963299236962).

The spelling of 12421254024541 in words is "twelve trillion, four hundred twenty-one billion, two hundred fifty-four million, twenty-four thousand, five hundred forty-one".