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12421254024677 is a prime number
BaseRepresentation
bin1011010011000000110001…
…1011110000110111100101
31121222110102112211210111102
42310300030123300313211
53112002212012242202
642230124553445445
72421256153105031
oct264601433606745
947873375753442
1012421254024677
113a59908091553
1214873a4a10885
136c141c464294
1430d29881b1c1
1516818a6e2d02
hexb4c0c6f0de5

12421254024677 has 2 divisors, whose sum is σ = 12421254024678. Its totient is φ = 12421254024676.

The previous prime is 12421254024559. The next prime is 12421254024689. The reversal of 12421254024677 is 77642045212421.

12421254024677 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12381960477601 + 39293547076 = 3518801^2 + 198226^2 .

It is a cyclic number.

It is not a de Polignac number, because 12421254024677 - 210 = 12421254023653 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12421254024077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6210627012338 + 6210627012339.

It is an arithmetic number, because the mean of its divisors is an integer number (6210627012339).

Almost surely, 212421254024677 is an apocalyptic number.

It is an amenable number.

12421254024677 is a deficient number, since it is larger than the sum of its proper divisors (1).

12421254024677 is an equidigital number, since it uses as much as digits as its factorization.

12421254024677 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1505280, while the sum is 47.

The spelling of 12421254024677 in words is "twelve trillion, four hundred twenty-one billion, two hundred fifty-four million, twenty-four thousand, six hundred seventy-seven".