12428246651 has 2 divisors, whose sum is σ = 12428246652. Its totient is φ = 12428246650.

The previous prime is 12428246639. The next prime is 12428246653. The reversal of 12428246651 is 15664282421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12428246651 - 2⁶ = 12428246587 is a prime.

It is a super-2 number, since 2×12428246651² (a number of 21 digits) contains 22 as substring.

Together with 12428246653, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12428246599 and 12428246608.

It is not a weakly prime, because it can be changed into another prime (12428246653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6214123325 + 6214123326.

It is an arithmetic number, because the mean of its divisors is an integer number (6214123326).

Almost surely, 2^12428246651 is an apocalyptic number.

12428246651 is a deficient number, since it is larger than the sum of its proper divisors (1).

12428246651 is an equidigital number, since it uses as much as digits as its factorization.

12428246651 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 184320, while the sum is 41.

The spelling of 12428246651 in words is "twelve billion, four hundred twenty-eight million, two hundred forty-six thousand, six hundred fifty-one".