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1243143151 is a prime number
BaseRepresentation
bin100101000011000…
…1101101111101111
310012122012012210221
41022012031233233
510021221040101
6323204512211
742543354025
oct11206155757
93178165727
101243143151
115887a3938
122a83ab667
1316a71b883
14bb160715
157420daa1
hex4a18dbef

1243143151 has 2 divisors, whose sum is σ = 1243143152. Its totient is φ = 1243143150.

The previous prime is 1243143149. The next prime is 1243143163. The reversal of 1243143151 is 1513413421.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1243143151 - 21 = 1243143149 is a prime.

It is a super-3 number, since 3×12431431513 (a number of 28 digits) contains 333 as substring.

Together with 1243143149, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1243144151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621571575 + 621571576.

It is an arithmetic number, because the mean of its divisors is an integer number (621571576).

Almost surely, 21243143151 is an apocalyptic number.

1243143151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1243143151 is an equidigital number, since it uses as much as digits as its factorization.

1243143151 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1440, while the sum is 25.

The square root of 1243143151 is about 35258.2352224271. The cubic root of 1243143151 is about 1075.2440479989.

Adding to 1243143151 its reverse (1513413421), we get a palindrome (2756556572).

The spelling of 1243143151 in words is "one billion, two hundred forty-three million, one hundred forty-three thousand, one hundred fifty-one".