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1243234000007 is a prime number
BaseRepresentation
bin10010000101110110100…
…001010101110010000111
311101212000010002212110222
4102011312201111302013
5130332120401000012
62351044523134555
7155551332432206
oct22056641256207
94355003085428
101243234000007
1143a28620020a
12180b4467445b
139030c68162c
144425c41123d
1522515589972
hex12176855c87

1243234000007 has 2 divisors, whose sum is σ = 1243234000008. Its totient is φ = 1243234000006.

The previous prime is 1243233999919. The next prime is 1243234000009. The reversal of 1243234000007 is 7000004323421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1243234000007 - 214 = 1243233983623 is a prime.

Together with 1243234000009, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1243234000007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1243234000009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621617000003 + 621617000004.

It is an arithmetic number, because the mean of its divisors is an integer number (621617000004).

Almost surely, 21243234000007 is an apocalyptic number.

1243234000007 is a deficient number, since it is larger than the sum of its proper divisors (1).

1243234000007 is an equidigital number, since it uses as much as digits as its factorization.

1243234000007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 26.

Adding to 1243234000007 its reverse (7000004323421), we get a palindrome (8243238323428).

The spelling of 1243234000007 in words is "one trillion, two hundred forty-three billion, two hundred thirty-four million, seven", and thus it is an aban number.