12433134103 has 8 divisors (see below), whose sum is σ = 13395842096. Its totient is φ = 11471328000.

The previous prime is 12433134089. The next prime is 12433134107. The reversal of 12433134103 is 30143133421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12433134103 - 2⁹ = 12433133591 is a prime.

It is a super-2 number, since 2×12433134103² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12433134107) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 196698 + ... + 252103.

It is an arithmetic number, because the mean of its divisors is an integer number (1674480262).

Almost surely, 2^12433134103 is an apocalyptic number.

12433134103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

12433134103 is a deficient number, since it is larger than the sum of its proper divisors (962707993).

12433134103 is a wasteful number, since it uses less digits than its factorization.

12433134103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 450945.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 12433134103 its reverse (30143133421), we get a palindrome (42576267524).

The spelling of 12433134103 in words is "twelve billion, four hundred thirty-three million, one hundred thirty-four thousand, one hundred three".