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1243400533 is a prime number
BaseRepresentation
bin100101000011100…
…1100100101010101
310012122200021212121
41022013030211111
510021302304113
6323214215541
742545505304
oct11207144525
93178607777
101243400533
1158895a251
122a84b45b1
1316a7aba7b
14bb1ca43b
157425ee8d
hex4a1cc955

1243400533 has 2 divisors, whose sum is σ = 1243400534. Its totient is φ = 1243400532.

The previous prime is 1243400531. The next prime is 1243400579. The reversal of 1243400533 is 3350043421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 852231249 + 391169284 = 29193^2 + 19778^2 .

It is an emirp because it is prime and its reverse (3350043421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1243400533 - 21 = 1243400531 is a prime.

Together with 1243400531, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1243400498 and 1243400507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1243400531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621700266 + 621700267.

It is an arithmetic number, because the mean of its divisors is an integer number (621700267).

Almost surely, 21243400533 is an apocalyptic number.

It is an amenable number.

1243400533 is a deficient number, since it is larger than the sum of its proper divisors (1).

1243400533 is an equidigital number, since it uses as much as digits as its factorization.

1243400533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 1243400533 is about 35261.8849893196. The cubic root of 1243400533 is about 1075.3182495276.

Adding to 1243400533 its reverse (3350043421), we get a palindrome (4593443954).

The spelling of 1243400533 in words is "one billion, two hundred forty-three million, four hundred thousand, five hundred thirty-three".