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1243451142511 is a prime number
BaseRepresentation
bin10010000110000011011…
…101101011000101101111
311101212120020200211222221
4102012003131223011233
5130333041443030021
62351122241220211
7155556610214554
oct22060335530557
94355506624887
101243451142511
1143a387831626
12180ba5331667
139034565b516
144427d1b6a2b
152252967d241
hex1218376b16f

1243451142511 has 2 divisors, whose sum is σ = 1243451142512. Its totient is φ = 1243451142510.

The previous prime is 1243451142509. The next prime is 1243451142539. The reversal of 1243451142511 is 1152411543421.

It is a weak prime.

It is an emirp because it is prime and its reverse (1152411543421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1243451142511 - 21 = 1243451142509 is a prime.

It is a super-3 number, since 3×12434511425113 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1243451142509, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1243451142911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 621725571255 + 621725571256.

It is an arithmetic number, because the mean of its divisors is an integer number (621725571256).

Almost surely, 21243451142511 is an apocalyptic number.

1243451142511 is a deficient number, since it is larger than the sum of its proper divisors (1).

1243451142511 is an equidigital number, since it uses as much as digits as its factorization.

1243451142511 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 19200, while the sum is 34.

Adding to 1243451142511 its reverse (1152411543421), we get a palindrome (2395862685932).

The spelling of 1243451142511 in words is "one trillion, two hundred forty-three billion, four hundred fifty-one million, one hundred forty-two thousand, five hundred eleven".