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12442120143 = 34147373381
BaseRepresentation
bin10111001011001101…
…11010111111001111
31012010010001012011120
423211212322333033
5200440140321033
65414341452023
7620220163515
oct134546727717
935103035146
1012442120143
115305286022
1224b2a11013
13123393298b
148606284b5
154cc4a41b3
hex2e59bafcf

12442120143 has 4 divisors (see below), whose sum is σ = 16589493528. Its totient is φ = 8294746760.

The previous prime is 12442120139. The next prime is 12442120147. The reversal of 12442120143 is 34102124421.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (12442120139) and next prime (12442120147).

It is a cyclic number.

It is not a de Polignac number, because 12442120143 - 22 = 12442120139 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12442120147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2073686688 + ... + 2073686693.

It is an arithmetic number, because the mean of its divisors is an integer number (4147373382).

Almost surely, 212442120143 is an apocalyptic number.

12442120143 is a deficient number, since it is larger than the sum of its proper divisors (4147373385).

12442120143 is an equidigital number, since it uses as much as digits as its factorization.

12442120143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4147373384.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 12442120143 its reverse (34102124421), we get a palindrome (46544244564).

The spelling of 12442120143 in words is "twelve billion, four hundred forty-two million, one hundred twenty thousand, one hundred forty-three".

Divisors: 1 3 4147373381 12442120143