12443343133 has 4 divisors (see below), whose sum is σ = 13400523388. Its totient is φ = 11486162880.

The previous prime is 12443343097. The next prime is 12443343169. The reversal of 12443343133 is 33134334421.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (12443343097) and next prime (12443343169).

It can be written as a sum of positive squares in 2 ways, for example, as 7838092089 + 4605251044 = 88533^2 + 67862^2 .

It is a cyclic number.

It is not a de Polignac number, because 12443343133 - 2¹³ = 12443334941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12443343095 and 12443343104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12443343173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 478590108 + ... + 478590133.

It is an arithmetic number, because the mean of its divisors is an integer number (3350130847).

Almost surely, 2^12443343133 is an apocalyptic number.

12443343133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12443343133 is a deficient number, since it is larger than the sum of its proper divisors (957180255).

12443343133 is an equidigital number, since it uses as much as digits as its factorization.

12443343133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 957180254.

The product of its digits is 31104, while the sum is 31.

Adding to 12443343133 its reverse (33134334421), we get a palindrome (45577677554).

The spelling of 12443343133 in words is "twelve billion, four hundred forty-three million, three hundred forty-three thousand, one hundred thirty-three".