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12444111303 = 313319079777
BaseRepresentation
bin10111001011011101…
…00001000111000111
31012010020210100112020
423211232201013013
5200441143030203
65414452254223
7620243125611
oct134556410707
935106710466
1012444111303
115306416008
1224b3611373
13123417c090
148609c5db1
154cc749153
hex2e5ba11c7

12444111303 has 8 divisors (see below), whose sum is σ = 17868467568. Its totient is φ = 7657914624.

The previous prime is 12444111293. The next prime is 12444111307. The reversal of 12444111303 is 30311144421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12444111303 - 225 = 12410556871 is a prime.

It is a super-2 number, since 2×124441113032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12444111307) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 159539850 + ... + 159539927.

It is an arithmetic number, because the mean of its divisors is an integer number (2233558446).

Almost surely, 212444111303 is an apocalyptic number.

12444111303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

12444111303 is a deficient number, since it is larger than the sum of its proper divisors (5424356265).

12444111303 is a wasteful number, since it uses less digits than its factorization.

12444111303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 319079793.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 12444111303 its reverse (30311144421), we get a palindrome (42755255724).

The spelling of 12444111303 in words is "twelve billion, four hundred forty-four million, one hundred eleven thousand, three hundred three".

Divisors: 1 3 13 39 319079777 957239331 4148037101 12444111303