Base | Representation |
---|---|
bin | 10111001011011101… |
… | …00001000111000111 |
3 | 1012010020210100112020 |
4 | 23211232201013013 |
5 | 200441143030203 |
6 | 5414452254223 |
7 | 620243125611 |
oct | 134556410707 |
9 | 35106710466 |
10 | 12444111303 |
11 | 5306416008 |
12 | 24b3611373 |
13 | 123417c090 |
14 | 8609c5db1 |
15 | 4cc749153 |
hex | 2e5ba11c7 |
12444111303 has 8 divisors (see below), whose sum is σ = 17868467568. Its totient is φ = 7657914624.
The previous prime is 12444111293. The next prime is 12444111307. The reversal of 12444111303 is 30311144421.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12444111303 - 225 = 12410556871 is a prime.
It is a super-2 number, since 2×124441113032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12444111307) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 159539850 + ... + 159539927.
It is an arithmetic number, because the mean of its divisors is an integer number (2233558446).
Almost surely, 212444111303 is an apocalyptic number.
12444111303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
12444111303 is a deficient number, since it is larger than the sum of its proper divisors (5424356265).
12444111303 is a wasteful number, since it uses less digits than its factorization.
12444111303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 319079793.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 12444111303 its reverse (30311144421), we get a palindrome (42755255724).
The spelling of 12444111303 in words is "twelve billion, four hundred forty-four million, one hundred eleven thousand, three hundred three".
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