Base | Representation |
---|---|
bin | 1011010100010111000011… |
… | …0100101010101111001001 |
3 | 1122001200012112202021211020 |
4 | 2311011300310222233021 |
5 | 3112342124224024431 |
6 | 42244515013223053 |
7 | 2423036105100606 |
oct | 265056064525711 |
9 | 48050175667736 |
10 | 12444413111241 |
11 | 3a6871185a011 |
12 | 148b988931a89 |
13 | 6c36704841b7 |
14 | 3104544bb6ad |
15 | 168a93979696 |
hex | b5170d2abc9 |
12444413111241 has 64 divisors (see below), whose sum is σ = 17555636133888. Its totient is φ = 7832768283648.
The previous prime is 12444413111233. The next prime is 12444413111269. The reversal of 12444413111241 is 14211131444421.
It is a happy number.
12444413111241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12444413111241 - 23 = 12444413111233 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (12444413191241) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 136936680 + ... + 137027526.
It is an arithmetic number, because the mean of its divisors is an integer number (274306814592).
Almost surely, 212444413111241 is an apocalyptic number.
It is an amenable number.
12444413111241 is a deficient number, since it is larger than the sum of its proper divisors (5111223022647).
12444413111241 is a wasteful number, since it uses less digits than its factorization.
12444413111241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91230.
The product of its digits is 12288, while the sum is 33.
Adding to 12444413111241 its reverse (14211131444421), we get a palindrome (26655544555662).
The spelling of 12444413111241 in words is "twelve trillion, four hundred forty-four billion, four hundred thirteen million, one hundred eleven thousand, two hundred forty-one".
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