Base | Representation |
---|---|
bin | 1011010100110100001001… |
… | …1010100000001101010111 |
3 | 1122002102100221010122121202 |
4 | 2311031002122200031113 |
5 | 3113004123423410111 |
6 | 42252250053103115 |
7 | 2423433505205423 |
oct | 265150232401527 |
9 | 48072327118552 |
10 | 12452224435031 |
11 | 3a70a60079207 |
12 | 14913a8927a9b |
13 | 6c43168a6294 |
14 | 310995aadb83 |
15 | 168d9e605b3b |
hex | b53426a0357 |
12452224435031 has 2 divisors, whose sum is σ = 12452224435032. Its totient is φ = 12452224435030.
The previous prime is 12452224434959. The next prime is 12452224435033. The reversal of 12452224435031 is 13053442225421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12452224435031 - 218 = 12452224172887 is a prime.
It is a super-2 number, since 2×124522244350312 (a number of 27 digits) contains 22 as substring.
Together with 12452224435033, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12452224435033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6226112217515 + 6226112217516.
It is an arithmetic number, because the mean of its divisors is an integer number (6226112217516).
Almost surely, 212452224435031 is an apocalyptic number.
12452224435031 is a deficient number, since it is larger than the sum of its proper divisors (1).
12452224435031 is an equidigital number, since it uses as much as digits as its factorization.
12452224435031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 230400, while the sum is 38.
The spelling of 12452224435031 in words is "twelve trillion, four hundred fifty-two billion, two hundred twenty-four million, four hundred thirty-five thousand, thirty-one".
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