Base | Representation |
---|---|
bin | 10010000111110010011… |
… | …101101000111000011101 |
3 | 11102001101000212120010011 |
4 | 102013302131220320131 |
5 | 130400400212420240 |
6 | 2352031124043221 |
7 | 155654012166625 |
oct | 22076235507035 |
9 | 4361330776104 |
10 | 1245313404445 |
11 | 440152a51580 |
12 | 181424b33511 |
13 | 9058140ac66 |
14 | 443b8659885 |
15 | 225d7dd46ea |
hex | 121f2768e1d |
1245313404445 has 32 divisors (see below), whose sum is σ = 1658090528640. Its totient is φ = 890207831040.
The previous prime is 1245313404409. The next prime is 1245313404463. The reversal of 1245313404445 is 5444043135421.
It is not a de Polignac number, because 1245313404445 - 213 = 1245313396253 is a prime.
It is a super-2 number, since 2×12453134044452 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1245313404398 and 1245313404407.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27680089 + ... + 27725041.
It is an arithmetic number, because the mean of its divisors is an integer number (51815329020).
Almost surely, 21245313404445 is an apocalyptic number.
It is an amenable number.
1245313404445 is a deficient number, since it is larger than the sum of its proper divisors (412777124195).
1245313404445 is a wasteful number, since it uses less digits than its factorization.
1245313404445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53565.
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 1245313404445 its reverse (5444043135421), we get a palindrome (6689356539866).
The spelling of 1245313404445 in words is "one trillion, two hundred forty-five billion, three hundred thirteen million, four hundred four thousand, four hundred forty-five".
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