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12453140003 is a prime number
BaseRepresentation
bin10111001100100001…
…11101011000100011
31012010212210001120112
423212100331120203
5201001000440003
65415414001535
7620412641423
oct134620753043
935125701515
1012453140003
115310522447
1224b66462ab
131235cc07c5
14861c96483
154cd42e3d8
hex2e643d623

12453140003 has 2 divisors, whose sum is σ = 12453140004. Its totient is φ = 12453140002.

The previous prime is 12453139949. The next prime is 12453140047. The reversal of 12453140003 is 30004135421.

12453140003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12453140003 - 212 = 12453135907 is a prime.

It is not a weakly prime, because it can be changed into another prime (12453140053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6226570001 + 6226570002.

It is an arithmetic number, because the mean of its divisors is an integer number (6226570002).

Almost surely, 212453140003 is an apocalyptic number.

12453140003 is a deficient number, since it is larger than the sum of its proper divisors (1).

12453140003 is an equidigital number, since it uses as much as digits as its factorization.

12453140003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 12453140003 its reverse (30004135421), we get a palindrome (42457275424).

The spelling of 12453140003 in words is "twelve billion, four hundred fifty-three million, one hundred forty thousand, three".