Base | Representation |
---|---|
bin | 1110110110001… |
… | …01010011100101 |
3 | 22200100021221112 |
4 | 13123011103211 |
5 | 223340241013 |
6 | 20205154405 |
7 | 3041400524 |
oct | 733052345 |
9 | 280307845 |
10 | 124540133 |
11 | 64332933 |
12 | 3585ba05 |
13 | 1ca565b3 |
14 | 1277c4bb |
15 | ae00ba8 |
hex | 76c54e5 |
124540133 has 2 divisors, whose sum is σ = 124540134. Its totient is φ = 124540132.
The previous prime is 124540111. The next prime is 124540153. The reversal of 124540133 is 331045421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 120846049 + 3694084 = 10993^2 + 1922^2 .
It is a cyclic number.
It is not a de Polignac number, because 124540133 - 210 = 124539109 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 124540099 and 124540108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124540153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62270066 + 62270067.
It is an arithmetic number, because the mean of its divisors is an integer number (62270067).
Almost surely, 2124540133 is an apocalyptic number.
It is an amenable number.
124540133 is a deficient number, since it is larger than the sum of its proper divisors (1).
124540133 is an equidigital number, since it uses as much as digits as its factorization.
124540133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 23.
The square root of 124540133 is about 11159.7550600360. The cubic root of 124540133 is about 499.3860905388.
Adding to 124540133 its reverse (331045421), we get a palindrome (455585554).
The spelling of 124540133 in words is "one hundred twenty-four million, five hundred forty thousand, one hundred thirty-three".
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