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1245500541403 is a prime number
BaseRepresentation
bin10010000111111101100…
…111100000100111011011
311102001212002000002202121
4102013331213200213123
5130401241114311103
62352101451042111
7155661443631466
oct22077547404733
94361762002677
101245500541403
11440239649318
12181477740337
13905b11104a1
14443d54502dd
15225e954c6bd
hex121fd9e09db

1245500541403 has 2 divisors, whose sum is σ = 1245500541404. Its totient is φ = 1245500541402.

The previous prime is 1245500541401. The next prime is 1245500541449. The reversal of 1245500541403 is 3041450055421.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1245500541403 - 21 = 1245500541401 is a prime.

It is a super-2 number, since 2×12455005414032 (a number of 25 digits) contains 22 as substring.

Together with 1245500541401, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1245500541401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 622750270701 + 622750270702.

It is an arithmetic number, because the mean of its divisors is an integer number (622750270702).

Almost surely, 21245500541403 is an apocalyptic number.

1245500541403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1245500541403 is an equidigital number, since it uses as much as digits as its factorization.

1245500541403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48000, while the sum is 34.

Adding to 1245500541403 its reverse (3041450055421), we get a palindrome (4286950596824).

The spelling of 1245500541403 in words is "one trillion, two hundred forty-five billion, five hundred million, five hundred forty-one thousand, four hundred three".